题目是英文的…怕翻译错于是把原题写上了…Find,initssimplestform,theargumentof(sinx+i(1-cosx))^2,wherexisanacuteangle.

Question

题目是英文的… 怕翻译错于是把原题写上了…
Find,in its simplest form,the argument of (sin x + i(1 - cos x))^2,where x is an acute angle.

Answer 1

化简(sin x + i(1 - cos x))^2,其中x是锐角(sin x + i(1 - cos x))^2=sin^2x+2isinx(1-cosx)-(1-cosx)^2 --------------- i^2=-1(复数)=1-cos^2x +2isinx(1-cosx)-(1+cos^2x-2cosx)=-2cos^2x+2cosx+2isinx(1-cosx)=2...