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数学化简【a+1分之1 + a-1分之1】除以a²-2a+1分之2a
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数学化简【a+1分之1 + a-1分之1】除以a²-2a+1分之2a
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解
[1/(a+1)+1/(a-1)]÷2a/(a²-2a+1)
=[(a-1)/(a-1)(a+1)+(a+1)/(a+1)(a-1)]×[(a-1)²/2a]
=[(a-1+a+1)/(a+1)(a-1)]×[(a-1)²/2a]
=[2a/(a-1)(a+1)]×[[(a-1)²/2a]
=(a-1)/(a+1)
[1/(a+1)+1/(a-1)]÷2a/(a²-2a+1)
=[(a-1)/(a-1)(a+1)+(a+1)/(a+1)(a-1)]×[(a-1)²/2a]
=[(a-1+a+1)/(a+1)(a-1)]×[(a-1)²/2a]
=[2a/(a-1)(a+1)]×[[(a-1)²/2a]
=(a-1)/(a+1)
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