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(4/x-5)+(x-3)/(12-x)=(x-45)/(x^2-17x+60)
题目详情
(4/x-5)+(x-3)/(12-x)=(x-45)/(x^2-17x+60)
▼优质解答
答案和解析
(4/x-5)+(x-3)/(12-x)=(x-45)/(x^2-17x+60)
(4/x-5)+(x-3)/(12-x)=(x-45)/(x-5)(x-12)
通分,两边同乘以(x-5)(x-12)得
4(x-12)-(x-3)(x-5)=x-45
-x^2+11x-18=0
x^2-11x+18=0
(x-2)(x-9)=0
x=2或x=9
经检验,都是方程的根!
(4/x-5)+(x-3)/(12-x)=(x-45)/(x-5)(x-12)
通分,两边同乘以(x-5)(x-12)得
4(x-12)-(x-3)(x-5)=x-45
-x^2+11x-18=0
x^2-11x+18=0
(x-2)(x-9)=0
x=2或x=9
经检验,都是方程的根!
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