一只空瓶质量是100g，装满水后，瓶水的总质量是600g；现改装某种液体，装满后，瓶和液体的总质量是500g．求：这种液体的密度？

Question

一只空瓶质量是100g，装满水后，瓶水的总质量是600g；现改装某种液体，装满后，瓶和液体的总质量是500g．求：这种液体的密度？

Answer 1

设液体的密度为ρ，根据题意得
(600g−100g)/(1g∕cm3)=(500g−100g)/(ρ)
解得ρ=0.8g/cm³．
答：这种液体的密度为0.8g/cm³． (600g−100g)/(1g∕cm3)600g−100g600g−100g600g−100g1g∕cm31g∕cm31g∕cm33=(500g−100g)/(ρ)
解得ρ=0.8g/cm³．
答：这种液体的密度为0.8g/cm³． (500g−100g)/(ρ)500g−100g500g−100g500g−100gρρρ
解得ρ=0.8g/cm³3．
答：这种液体的密度为0.8g/cm³3．