早教吧作业答案频道 -->英语-->
英语翻译申请住XX(XX)就近工作尊敬的XXXXX我是PNTQCXXX,现暂住深圳市.几天前公司告知CHICCO和PNT两组QC以后会合并,我看到QC的工作安排表中XX(XX)的工作量比较繁忙(附件是最近的QC工作安
题目详情
英语翻译
申请住XX(XX)就近工作
尊敬的XXXXX
我是PNT QC XXX,现暂住深圳市.几天前公司告知CHICCO和PNT两组QC以后会合并,我看到QC的工作安排表中XX(XX)的工作量比较繁忙(附件是最近的QC工作安排表),我是XX人,在XX省XX市有年老的妈妈和两个小孩在家乡生活和读书.那里去XXXX也比较近,常住那里就近工作的话,不但能为我的家庭带来和谐,也能为公司节约差旅费的开销,所以我向公司领导申请常住XX就近工作,请给予考虑.
申请住XX(XX)就近工作
尊敬的XXXXX
我是PNT QC XXX,现暂住深圳市.几天前公司告知CHICCO和PNT两组QC以后会合并,我看到QC的工作安排表中XX(XX)的工作量比较繁忙(附件是最近的QC工作安排表),我是XX人,在XX省XX市有年老的妈妈和两个小孩在家乡生活和读书.那里去XXXX也比较近,常住那里就近工作的话,不但能为我的家庭带来和谐,也能为公司节约差旅费的开销,所以我向公司领导申请常住XX就近工作,请给予考虑.
▼优质解答
答案和解析
The application of XX (XX) to work
Dear XXXXX
I am PNT QC XXX, now living in Shenzhen city. Company a few days ago toldCHICCO and PNT two QC will merge, I saw QC work table in XX (XX)workload is busy (Annex table QC work lately), I was XX, old mother and two children living at home and reading in XX province XX city. Where XXXX is relatively recent, resident there to work, not only for my family to bring harmony, can travel for the companies to save costs, so I to the leadership of the company to apply for resident XX at work, please consider. Thank you.
Dear XXXXX
I am PNT QC XXX, now living in Shenzhen city. Company a few days ago toldCHICCO and PNT two QC will merge, I saw QC work table in XX (XX)workload is busy (Annex table QC work lately), I was XX, old mother and two children living at home and reading in XX province XX city. Where XXXX is relatively recent, resident there to work, not only for my family to bring harmony, can travel for the companies to save costs, so I to the leadership of the company to apply for resident XX at work, please consider. Thank you.
看了 英语翻译申请住XX(XX)就...的网友还看了以下:
高中二项式系数(1+x)+(1+x)^2+(1+x)^3+……+(1+x)^n的展开式中各项系数和为 2020-03-30 …
函数u=in(X^2+Y^2+Z^2)在点M(1,2,-2)处梯度gradu!M是多少幂级数1-X 2020-04-27 …
1.求幂级数(这是个求和符号)((n-1)/(n+1))*x^n的收敛域和函数s(x)2.解微分方 2020-05-12 …
我要提问一道初中二年级的一元二次方程数学题已知:关于X的方程X的平方+MX+N=0有相等的实根求证 2020-05-16 …
x+x^2+x^3+.+x^n的计算公式是什么?x+x^2+x^3+.+x^n的计算公式是什么x^ 2020-06-02 …
在公差不为零的等差数列{x(n)}和等比数列{y(n)}中,已知x1=1,且x1=y1,x2=y2 2020-06-04 …
在(1+x)^n的展开式中,已知第三项与第五项的系数相等(1)求(x^2-1/x)^n展开式中的系 2020-06-07 …
设y=x^u,求y^n=?这是书上的解法是y'=ux^(u-1),y''=u(u-1)x^(u-2 2020-06-18 …
1.判别级数∑(∞,n=1)(1000)^n/n!的敛散性2.求幂级数∑(∞,n=1)(n+1)^ 2020-06-27 …
当x→0时e^x是x^n的高阶无穷小吗?x→+∞e^x的增长速度比x^n当x→0时e^x是x^n的 2020-07-01 …