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（2012•北京模拟）（1）3015-3015÷15（2）1314-1315+114-215（3）（1-14+13）÷26（4）6.3÷[（417-0.07×50）÷127]．
题目详情
| 13 |
| 14 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
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| 2 |
| 7 |
| 13 |
| 14 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 1 |
| 14 |
| 2 |
| 15 |
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 2 |
| 15 |
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
| 1 |
| 4 |
| 1 |
| 3 |
（4）6.3÷[（4
| 1 |
| 7 |
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▼优质解答
答案和解析
（1）3015-3015÷15，
=3015-201，
=3015-200-1，
=2815-1，
=2814；
（2）
-
+
-
，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1314 14 14-
+
-
，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1315 15 15+
-
，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 114 14 14-
，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
2 2 215 15 15，
=（
+
）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1314 14 14+
1 1 114 14 14）-（
+
），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1315 15 15+
2 2 215 15 15），
=1-1，
=0；
（3）（1-
+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 14 4 4+
）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 13 3 3）÷26，
=（
+
）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
3 3 34 4 4+
1 1 13 3 3）÷26，
=
÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
13 13 1312 12 12÷26，
=
；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 124 24 24；
（4）6.3÷[（4
-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 17 7 7-0.07×50）÷1
]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
2 2 27 7 7]，
=6.3÷[（4
-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
1 1 17 7 7-3.5）÷1
]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
2 2 27 7 7]，
=6.3÷[
÷1
]，
=6.3÷
，
=12.6．
9 9 914 14 14÷1
2 2 27 7 7]，
=6.3÷
，
=12.6．
1 1 12 2 2，
=12.6．
=3015-201，
=3015-200-1，
=2815-1，
=2814；
（2）
| 13 |
| 14 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 14 |
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 15 |
| 1 |
| 14 |
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 14 |
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 2 |
| 15 |
=（
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 14 |
| 1 |
| 14 |
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 15 |
| 2 |
| 15 |
=1-1，
=0；
（3）（1-
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 4 |
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 3 |
=（
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 3 |
| 4 |
| 1 |
| 3 |
=
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 13 |
| 12 |
=
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 24 |
（4）6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 2 |
| 7 |
=6.3÷[（4
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 7 |
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 2 |
| 7 |
=6.3÷[
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 9 |
| 14 |
| 2 |
| 7 |
=6.3÷
| 1 |
| 2 |
=12.6．
| 1 |
| 2 |
=12.6．
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