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用递等式计算.(能简算的要简算)35×(512÷34)56+712÷123.7×99+3.737+511+47+611360÷15+2.5×1623÷〔1-(13-14)〕
题目详情
用递等式计算. (能简算的要简算)
|
| 3.7×99+3.7 | ||||||||||||||
| 360÷15+2.5×16 |
|
用递等式计算. (能简算的要简算)
|
| 3.7×99+3.7 | ||||||||||||||
| 360÷15+2.5×16 |
|
3 |
5 |
5 |
12 |
3 |
4 |
5 |
6 |
7 |
12 |
1 |
2 |
3 |
5 |
5 |
12 |
3 |
4 |
3 |
5 |
5 |
12 |
3 |
4 |
3 |
5 |
5 |
12 |
3 |
4 |
5 |
12 |
3 |
4 |
3 |
4 |
5 |
6 |
7 |
12 |
1 |
2 |
5 |
6 |
7 |
12 |
1 |
2 |
5 |
6 |
7 |
12 |
1 |
2 |
7 |
12 |
1 |
2 |
1 |
2 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
2 |
3 |
1 |
3 |
1 |
4 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
5 |
11 |
4 |
7 |
6 |
11 |
4 |
7 |
6 |
11 |
6 |
11 |
2 |
3 |
1 |
3 |
1 |
4 |
2 |
3 |
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3 |
1 |
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1 |
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1 |
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4 |
▼优质解答
答案和解析
(1)
×(
÷
),
=
×
,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 35 5 5×(
÷
),
=
×
,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 512 12 12÷
),
=
×
,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 34 4 4),
=
×
,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 35 5 5×
5 5 59 9 9,
=
;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
1 1 13 3 3;
(2)
+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 56 6 6+
÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
7 7 712 12 12÷
,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
1 1 12 2 2,
=
+
,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 56 6 6+
7 7 76 6 6,
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 37 7 7+
+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 511 11 11+
+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
4 4 47 7 7+
,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
6 6 611 11 11,
=(
+
)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
3 3 37 7 7+
4 4 47 7 7)+(
+
),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
5 5 511 11 11+
6 6 611 11 11),
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
2 2 23 3 3÷〔1-(
-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
1 1 13 3 3-
)〕,
=
÷〔1-
〕,
=
÷
,
=
.
1 1 14 4 4)〕,
=
÷〔1-
〕,
=
÷
,
=
.
2 2 23 3 3÷〔1-
〕,
=
÷
,
=
.
1 1 112 12 12〕,
=
÷
,
=
.
2 2 23 3 3÷
,
=
.
11 11 1112 12 12,
=
.
8 8 811 11 11.
3 |
5 |
5 |
12 |
3 |
4 |
=
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
5 |
5 |
12 |
3 |
4 |
=
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
12 |
3 |
4 |
=
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
4 |
=
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
5 |
5 |
9 |
=
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
3 |
(2)
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
6 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
7 |
12 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
2 |
=
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
6 |
7 |
6 |
=2;
(3)3.7×99+3.7,
=3.7×(99+1),
=3.7×100,
=370;
(4)
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
7 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
4 |
7 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
6 |
11 |
=(
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
3 |
7 |
4 |
7 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
5 |
11 |
6 |
11 |
=1+1,
=2;
(5)360÷15+2.5×16,
=24+40,
=64;
(6)
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
2 |
3 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
3 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
4 |
=
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
2 |
3 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
1 |
12 |
=
2 |
3 |
11 |
12 |
=
8 |
11 |
2 |
3 |
11 |
12 |
=
8 |
11 |
11 |
12 |
=
8 |
11 |
8 |
11 |
看了 用递等式计算.(能简算的要简...的网友还看了以下:
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PI函数可根据下面公式,计算精度满足eps时的值.请填空.PI函数可根据下面公式,计算精度满足eps 2020-11-03 …
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设非空集合A{1,2,3,4,5,6,7},且当a∈A时必有8-a∈A,这样的A共有(15)个.{4 2020-12-07 …
■■■■■······■■■■■■■■■(1)如图,第n个图形中有多少个小正方形?你是如何计算的?( 2020-12-28 …