早教吧作业答案频道 -->数学-->
计算下面各题，能简算的要简算．23+15+45+134-511-61118×58+18×41+1845÷47×54-126÷310-310÷638×[（12+25）×23]．
题目详情
计算下面各题，能简算的要简算．
| 4-
| ||||||||||||||
|
| ||||||||||||||
6÷
|
|
| 2 |
| 3 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 3 |
| 5 |
| 11 |
| 6 |
| 11 |
| 2 |
| 3 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 3 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 3 |
| 4 |
| 5 |
| 1 |
| 3 |
| 1 |
| 3 |
| 5 |
| 11 |
| 6 |
| 11 |
| 5 |
| 11 |
| 6 |
| 11 |
| 5 |
| 11 |
| 6 |
| 11 |
| 6 |
| 11 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 4 |
| 5 |
| 4 |
| 7 |
| 5 |
| 4 |
| 1 |
| 2 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 4 |
| 5 |
| 4 |
| 7 |
| 5 |
| 4 |
| 1 |
| 2 |
| 4 |
| 5 |
| 4 |
| 7 |
| 5 |
| 4 |
| 1 |
| 2 |
| 4 |
| 5 |
| 4 |
| 7 |
| 5 |
| 4 |
| 1 |
| 2 |
| 4 |
| 7 |
| 5 |
| 4 |
| 1 |
| 2 |
| 5 |
| 4 |
| 1 |
| 2 |
| 1 |
| 2 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 8 |
| 1 |
| 2 |
| 2 |
| 5 |
| 2 |
| 3 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 8 |
| 1 |
| 2 |
| 2 |
| 5 |
| 2 |
| 3 |
| 3 |
| 8 |
| 1 |
| 2 |
| 2 |
| 5 |
| 2 |
| 3 |
| 3 |
| 8 |
| 1 |
| 2 |
| 2 |
| 5 |
| 2 |
| 3 |
| 1 |
| 2 |
| 2 |
| 5 |
| 2 |
| 3 |
| 2 |
| 5 |
| 2 |
| 3 |
| 2 |
| 3 |
▼优质解答
答案和解析
（1）23+15+45+13，=（23+13）+（15+45），=1+1，=2；（2）4-（511+611），=4-1，=3；（3）18×58+18×41+18，=18×（58+41+1），=18×100，=12.5；（4）45÷47×54-12，=45×54×74-12，=1×74-12，=74-12，=54；（...
看了 计算下面各题，能简算的要简算...的网友还看了以下：
1.25*2.41.25乘2.4、15.5-5.5乘1.6+0.53、怎樣簡便計算? 2020-04-27 …
(-125)*(-25)*(-5)*2*(-4)*(-8) =要简便算式 2020-05-17 …
字数太多在下面,4(x+1)²=25(x-2)²4(x+1)²-25(x-2)²=0(2x+2)² 2020-06-05 …
数学单选题急急急在线等1）把25*4=50*2改写成比例是（）A.25：4=50：2B.25：2= 2020-07-13 …
1.（x^2-3)^2+2(x^2-3)(x-3)+(x-3)^22.(x+1)(x+3)(x+5 2020-07-18 …
直接写出得数．34×200=300÷15=840÷40=25+25×3=26×300=157-49 2020-07-18 …
计算（1）1.3×14−12×0.25+0.2÷4（2）[（113−815)×75%+14]÷17 2020-07-19 …
数据结构问题已知一个图的顶点集V和边集E分别为：V={0,1,2,3,4,5,6,7}E={（0, 2020-07-30 …
3x+10y-25=0与x^2/25+y^2/4=1的公共点坐标我记得使用联立法解得 2020-10-31 …
直线和椭圆的交点如何求1)3x+10y-25=0,x^2/25+y^2/4=1,设x=5cosa,y 2020-10-31 …