早教吧作业答案频道 -->其他-->
(2007•华亭县)计算.(1)78-(12+35)×511(2)3.68×[1÷(2.1-2.09)](3)7.8÷[32×(1-58)+3.6].
题目详情
(2007•华亭县)计算.
(1)
-(
+
)×
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
)+3.6].
-(
+
)×
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
)+3.6].
7 7 8 8
+
)×
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
)+3.6].
1 1 2 2
)×
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
)+3.6].
3 3 5 5
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
)+3.6].
5 5 11 11
)+3.6].
5 5 8 8
(1)
7 |
8 |
1 |
2 |
3 |
5 |
5 |
11 |
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
5 |
8 |
7 |
8 |
1 |
2 |
3 |
5 |
5 |
11 |
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
5 |
8 |
7 |
8 |
1 |
2 |
3 |
5 |
5 |
11 |
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
5 |
8 |
1 |
2 |
3 |
5 |
5 |
11 |
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
5 |
8 |
3 |
5 |
5 |
11 |
(2)3.68×[1÷(2.1-2.09)]
(3)7.8÷[32×(1-
5 |
8 |
5 |
11 |
5 |
8 |
5 |
8 |
▼优质解答
答案和解析
(1)
-(
+
)×
,
=
-
×
,
=
-
,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
7 7 78 8 8-(
+
)×
,
=
-
×
,
=
-
,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
1 1 12 2 2+
)×
,
=
-
×
,
=
-
,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
3 3 35 5 5)×
,
=
-
×
,
=
-
,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
5 5 511 11 11,
=
-
×
,
=
-
,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
7 7 78 8 8-
×
,
=
-
,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
11 11 1110 10 10×
,
=
-
,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
5 5 511 11 11,
=
-
,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
7 7 78 8 8-
,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
1 1 12 2 2,
=
;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
3 3 38 8 8;
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
5 5 58 8 8)+3.6],
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
3 3 38 8 8+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
7 |
8 |
1 |
2 |
3 |
5 |
5 |
11 |
=
7 |
8 |
11 |
10 |
5 |
11 |
=
7 |
8 |
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
7 |
8 |
1 |
2 |
3 |
5 |
5 |
11 |
=
7 |
8 |
11 |
10 |
5 |
11 |
=
7 |
8 |
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
1 |
2 |
3 |
5 |
5 |
11 |
=
7 |
8 |
11 |
10 |
5 |
11 |
=
7 |
8 |
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
3 |
5 |
5 |
11 |
=
7 |
8 |
11 |
10 |
5 |
11 |
=
7 |
8 |
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
5 |
11 |
=
7 |
8 |
11 |
10 |
5 |
11 |
=
7 |
8 |
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
7 |
8 |
11 |
10 |
5 |
11 |
=
7 |
8 |
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
11 |
10 |
5 |
11 |
=
7 |
8 |
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
5 |
11 |
=
7 |
8 |
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
7 |
8 |
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
1 |
2 |
=
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
3 |
8 |
(2)3.68×[1÷(2.1-2.09)],
=3.68×[1÷0.01],
=3.68×100,
=368;
(3)7.8÷[32×(1-
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
5 |
8 |
=7.8÷[32×
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
3 |
8 |
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
看了 (2007•华亭县)计算.(...的网友还看了以下:
直接写出得数529+198=2.05×4=8×12.5%=0.28÷0.7=16+25=0.37+ 2020-04-07 …
填空题.问8/5的分数单位是(),它有()个这个样的分数单位.问12/7里有()个12/1,()个 2020-05-15 …
excel 区域内数字统计如何统计下面这组数据:A B C D E F G H I1 6 9 12 2020-05-16 …
4分之1×(8+5分之4)等于多少?1.(2分之1-3分之1)×6=9×5分之4+9×5分之1=5 2020-05-16 …
公考数字推理题本人急用先谢勒..一60,30,20,15,12,().A.10B.8C.6D.4二 2020-06-26 …
简便计算1÷(2÷3)÷(3÷4)÷(4÷5)(12.3+23.41+34.12+41.23)简便 2020-07-18 …
1.4/5X-(465-X)x2/3=202.X-1/5X=44-X+2843.(3/8X-12) 2020-07-18 …
用递等式计算.(能简算的要写出简算过程)(1)8.5×[(2.36+2.42)÷0.25](2)3 2020-07-18 …
把下面各比化成最简单的整数比2/5:32/5:327:2/31/8:1、25108:962:1、2 2020-07-19 …
直接写得数:1.25×8=5×2.4=0.36÷3.6=5.6+4.04=4.6×0.1=72.5÷ 2020-11-19 …