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用递等式计算.①28.49÷7.4×0.32;②(514÷1.25+112)×13-0.975;③(0.2+13)÷23÷0.6;④[(615-0.45)÷1518]÷(113÷6).

题目详情
用递等式计算.
①28.49÷7.4×0.32;            
②(5
1
4
÷1.25+1
1
2
)×
1
3
-0.975;
③(0.2+
1
3
)÷
2
3
÷0.6;         
④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6).


1
4
÷1.25+1
1
2
)×
1
3
-0.975;
③(0.2+
1
3
)÷
2
3
÷0.6;         
④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6).
1
4
1144
1
2
)×
1
3
-0.975;
③(0.2+
1
3
)÷
2
3
÷0.6;         
④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6).
1
2
1122
1
3
-0.975;
③(0.2+
1
3
)÷
2
3
÷0.6;         
④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6).
1
3
1133
1
3
)÷
2
3
÷0.6;         
④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6).
1
3
1133
2
3
÷0.6;         
④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6).
2
3
2233
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6).
1
5
1155
5
18
]÷(1
1
3
÷6).
5
18
551818
1
3
÷6).
1
3
1133
▼优质解答
答案和解析
①28.49÷7.4×0.32
=3.85×0.32
=1.232;

②(5
1
4
÷1.25+1
1
2
)×
1
3
-0.975
=(4.2+1.5)×
1
3
-0.975
=5.7×
1
3
-0.975
=1.9-0.975
=0.925;

③(0.2+
1
3
)÷
2
3
÷0.6
=
8
15
×
3
2
×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
1
4
111444÷1.25+1
1
2
)×
1
3
-0.975
=(4.2+1.5)×
1
3
-0.975
=5.7×
1
3
-0.975
=1.9-0.975
=0.925;

③(0.2+
1
3
)÷
2
3
÷0.6
=
8
15
×
3
2
×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
1
2
111222)×
1
3
-0.975
=(4.2+1.5)×
1
3
-0.975
=5.7×
1
3
-0.975
=1.9-0.975
=0.925;

③(0.2+
1
3
)÷
2
3
÷0.6
=
8
15
×
3
2
×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
1
3
111333-0.975
=(4.2+1.5)×
1
3
-0.975
=5.7×
1
3
-0.975
=1.9-0.975
=0.925;

③(0.2+
1
3
)÷
2
3
÷0.6
=
8
15
×
3
2
×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
1
3
111333-0.975
=5.7×
1
3
-0.975
=1.9-0.975
=0.925;

③(0.2+
1
3
)÷
2
3
÷0.6
=
8
15
×
3
2
×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
1
3
111333-0.975
=1.9-0.975
=0.925;

③(0.2+
1
3
)÷
2
3
÷0.6
=
8
15
×
3
2
×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
1
3
111333)÷
2
3
÷0.6
=
8
15
×
3
2
×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
2
3
222333÷0.6
=
8
15
×
3
2
×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
8
15
888151515×
3
2
×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
3
2
333222×
5
3

=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
5
3
555333
=
4
3


④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
4
3
444333;

④[(6
1
5
-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
1
5
111555-0.45)÷1
5
18
]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
5
18
555181818]÷(1
1
3
÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
1
3
111333÷6)
=[
23
4
÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
23
4
232323444÷1
5
18
2
9

=
9
2
×
9
2

=
81
4
5
18
555181818]÷
2
9

=
9
2
×
9
2

=
81
4
2
9
222999
=
9
2
×
9
2

=
81
4
9
2
999222×
9
2

=
81
4
9
2
999222
=
81
4
81
4
818181444.