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计算:①222×44+889×88=②100-99+98-97+96-95+…+42-41+40=③11×2+12×3+13×4+14×5=④1+12+13=⑤13×(4.3×335-3.6+6.7÷518)-(1.23÷1323-5-0.09)=

题目详情
计算:
①222×44+889×88=
②100-99+98-97+96-95+…+42-41+40=
1
1×2
+
1
2×3
+
1
3×4
+
1
4×5
=
④1+
1
2+
1
3
=
1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09)=



1
1×2
+
1
2×3
+
1
3×4
+
1
4×5
=
④1+
1
2+
1
3
=
1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09)=
1
1×2
111×21×2
1
2×3
+
1
3×4
+
1
4×5
=
④1+
1
2+
1
3
=
1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09)=
1
2×3
112×32×3
1
3×4
+
1
4×5
=
④1+
1
2+
1
3
=
1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09)=
1
3×4
113×43×4
1
4×5
=
④1+
1
2+
1
3
=
1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09)=
1
4×5
114×54×5
1
2+
1
3
=
1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09)=
1
2+
1
3
112+
1
3
2+
1
3
1
3
1133
1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09)=
1
3
1133
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09)=
3
5
3355
5
18
)-(1.23÷13
2
3
-5-0.09)=
5
18
551818
2
3
-5-0.09)=
2
3
2233
▼优质解答
答案和解析
①222×44+889×88,
=111×2×44+889×88,
=111×88+889×88,
=(111+889)×88,
=1000×88,
=88000;


②100-99+98-97+96-95+…+42-41+40,
=(100-99)+(98-97)+(96-95)+…+(42-41)+40,
=1×30+40,
=70;


1
1×2
+
1
2×3
+
1
3×4
+
1
4×5

=1-
1
2
+
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
1×2
1111×21×21×2+
1
2×3
+
1
3×4
+
1
4×5

=1-
1
2
+
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
2×3
1112×32×32×3+
1
3×4
+
1
4×5

=1-
1
2
+
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
3×4
1113×43×43×4+
1
4×5

=1-
1
2
+
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
4×5
1114×54×54×5,
=1-
1
2
+
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
2
111222+
1
2
-
1
3
+
1
3
-
1
4
+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
2
111222-
1
3
+
1
3
-
1
4
+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
3
111333+
1
3
-
1
4
+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
3
111333-
1
4
+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
4
111444+
1
4
-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
4
111444-
1
5

=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
5
111555,
=
4
5


④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
4
5
444555;

④1+
1
2+
1
3

=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
2+
1
3
1112+
1
3
2+
1
3
2+
1
3
111333,
=1+1÷(2+
1
3
),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
3
111333),
=1+1÷
7
3

=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
7
3
777333,
=1
3
7



1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
3
7
333777;


1
3
×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
3
111333×(4.3×3
3
5
-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
3
5
333555-3.6+6.7÷
5
18
)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
5
18
555181818)-(1.23÷13
2
3
-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
2
3
222333-5-0.09),
=
1
3
×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
3
111333×(4.3×3.6-3.6+6.7×3.6)-(0.09-0.09-5),
=
1
3
×3.6×(4.3-1+6.7)+5,
=12+5,
=17.
1
3
111333×3.6×(4.3-1+6.7)+5,
=12+5,
=17.