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用简便方法计算0.95×27+57×0.951419-417+519-31710000÷25÷8÷459+79+3-1.625-2.375
题目详情
用简便方法计算 0.95×
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10000÷25÷8÷4 |
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用简便方法计算 0.95×
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10000÷25÷8÷4 |
|
0.95×
2 |
7 |
5 |
7 |
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
0.95×
2 |
7 |
5 |
7 |
2 |
7 |
5 |
7 |
2 |
7 |
5 |
7 |
5 |
7 |
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
4 |
17 |
5 |
19 |
3 |
17 |
5 |
19 |
3 |
17 |
3 |
17 |
5 |
9 |
7 |
9 |
5 |
9 |
7 |
9 |
5 |
9 |
7 |
9 |
5 |
9 |
7 |
9 |
7 |
9 |
▼优质解答
答案和解析
(1)0.95×
+
×0.95
=0.95×(
+
)
=0.95×1
=0.95;
(2)
-
+
-
=(
+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
2 2 27 7 7+
×0.95
=0.95×(
+
)
=0.95×1
=0.95;
(2)
-
+
-
=(
+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
5 5 57 7 7×0.95
=0.95×(
+
)
=0.95×1
=0.95;
(2)
-
+
-
=(
+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
2 2 27 7 7+
)
=0.95×1
=0.95;
(2)
-
+
-
=(
+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
5 5 57 7 7)
=0.95×1
=0.95;
(2)
-
+
-
=(
+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
14 14 1419 19 19-
+
-
=(
+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
4 4 417 17 17+
-
=(
+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
5 5 519 19 19-
=(
+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
3 3 317 17 17
=(
+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
14 14 1419 19 19+
)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
5 5 519 19 19)-(
+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
4 4 417 17 17+
)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
3 3 317 17 17)
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
5 5 59 9 9+
+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
7 7 79 9 9+3-1.625-2.375
=(
+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
5 5 59 9 9+
)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
7 7 79 9 9)+3-(1.625+2.375)
=1
+3-4
=4
-4
=
.
1 1 13 3 3+3-4
=4
-4
=
.
1 1 13 3 3-4
=
.
1 1 13 3 3.
2 |
7 |
5 |
7 |
=0.95×(
2 |
7 |
5 |
7 |
=0.95×1
=0.95;
(2)
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
=(
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
2 |
7 |
5 |
7 |
=0.95×(
2 |
7 |
5 |
7 |
=0.95×1
=0.95;
(2)
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
=(
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
5 |
7 |
=0.95×(
2 |
7 |
5 |
7 |
=0.95×1
=0.95;
(2)
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
=(
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
2 |
7 |
5 |
7 |
=0.95×1
=0.95;
(2)
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
=(
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
5 |
7 |
=0.95×1
=0.95;
(2)
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
=(
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
14 |
19 |
4 |
17 |
5 |
19 |
3 |
17 |
=(
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
4 |
17 |
5 |
19 |
3 |
17 |
=(
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
5 |
19 |
3 |
17 |
=(
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
3 |
17 |
=(
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
14 |
19 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
5 |
19 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
4 |
17 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
3 |
17 |
=1-1
=0;
(3)10000÷25÷8÷4
=10000÷8÷25÷4
=(10000÷8)÷(25×4)
=1250÷100
=12.5;
(4)
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
5 |
9 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
7 |
9 |
=(
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
5 |
9 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
7 |
9 |
=1
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
1 |
3 |
=4
1 |
3 |
=
1 |
3 |
1 |
3 |
=
1 |
3 |
1 |
3 |
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