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计算题:(1)312+(−12)−(−13)+223(2)(23−14−38+524)×48(3)-18÷(-3)2+5×(−12)2-(-15)÷5(4)[-38-(-1)7+(-3)8]×[-52].
题目详情
计算题:
(1)3
+(−
)−(−
)+2
(2)(
−
−
+
)×48
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].
+(−
)−(−
)+2
(2)(
−
−
+
)×48
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].
1 1 2 2
1 1 2 2
1 1 3 3
(2)(
−
−
+
)×48
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].
2 2 3 3
(
−
−
+
)×48
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].
2 2 3 3
1 1 4 4
3 3 8 8
5 5 24 24
2(−
)2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].
1 1 2 2 )2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].)2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].
8782
(1)3
1 |
2 |
1 |
2 |
1 |
3 |
2 |
3 |
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
(3)-18÷(-3)2+5×(−
1 |
2 |
(4)[-38-(-1)7+(-3)8]×[-52].
1 |
2 |
1 |
2 |
1 |
3 |
2 |
3 |
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
(3)-18÷(-3)2+5×(−
1 |
2 |
(4)[-38-(-1)7+(-3)8]×[-52].
1 |
2 |
1 |
2 |
1 |
3 |
2 |
3 |
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
(3)-18÷(-3)2+5×(−
1 |
2 |
(4)[-38-(-1)7+(-3)8]×[-52].
2 |
3 |
(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
(3)-18÷(-3)2+5×(−
1 |
2 |
(4)[-38-(-1)7+(-3)8]×[-52].
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
2(−
1 |
2 |
(4)[-38-(-1)7+(-3)8]×[-52].
1 |
2 |
(4)[-38-(-1)7+(-3)8]×[-52].)2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].2-(-15)÷5
(4)[-38-(-1)7+(-3)8]×[-52].
8782
▼优质解答
答案和解析
(1)3
+(−
)−(−
)+2
=(3
-
)+(
+2
)
=3+3
=6;
(2)(
−
−
+
)×48
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 1 12 2 2+(−
1 1 12 2 2)−(−
1 1 13 3 3)+2
=(3
-
)+(
+2
)
=3+3
=6;
(2)(
−
−
+
)×48
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
2 2 23 3 3
=(3
-
)+(
+2
)
=3+3
=6;
(2)(
−
−
+
)×48
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 1 12 2 2-
)+(
+2
)
=3+3
=6;
(2)(
−
−
+
)×48
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 1 12 2 2)+(
+2
)
=3+3
=6;
(2)(
−
−
+
)×48
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 1 13 3 3+2
)
=3+3
=6;
(2)(
−
−
+
)×48
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
2 2 23 3 3)
=3+3
=6;
(2)(
−
−
+
)×48
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
)2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25. (
2 2 23 3 3−
1 1 14 4 4−
3 3 38 8 8+
5 5 524 24 24)×48
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)22+5×(−
)2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25. (−
1 1 12 2 2)2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25. 2-(-15)÷5
=-18÷9+5×
+3
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 1 14 4 4+3
=-2+1.25+3
=2.25;
(4)[-388-(-1)77+(-3)88]×[-522]
=[-388+388+1]×(-25)
=1×(-25)
=-25.
1 |
2 |
1 |
2 |
1 |
3 |
2 |
3 |
=(3
1 |
2 |
1 |
2 |
1 |
3 |
2 |
3 |
=3+3
=6;
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
1 |
2 |
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 |
2 |
1 |
2 |
1 |
3 |
2 |
3 |
=(3
1 |
2 |
1 |
2 |
1 |
3 |
2 |
3 |
=3+3
=6;
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
1 |
2 |
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
2 |
3 |
=(3
1 |
2 |
1 |
2 |
1 |
3 |
2 |
3 |
=3+3
=6;
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
1 |
2 |
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 |
2 |
1 |
2 |
1 |
3 |
2 |
3 |
=3+3
=6;
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
1 |
2 |
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 |
2 |
1 |
3 |
2 |
3 |
=3+3
=6;
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
1 |
2 |
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 |
3 |
2 |
3 |
=3+3
=6;
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
1 |
2 |
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
2 |
3 |
=3+3
=6;
(2)(
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)2+5×(−
1 |
2 |
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25. (
2 |
3 |
1 |
4 |
3 |
8 |
5 |
24 |
=32-12-18+10
=42-30
=12;
(3)-18÷(-3)22+5×(−
1 |
2 |
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25. (−
1 |
2 |
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25. 2-(-15)÷5
=-18÷9+5×
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-38-(-1)7+(-3)8]×[-52]
=[-38+38+1]×(-25)
=1×(-25)
=-25.
1 |
4 |
=-2+1.25+3
=2.25;
(4)[-388-(-1)77+(-3)88]×[-522]
=[-388+388+1]×(-25)
=1×(-25)
=-25.
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