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化简.(1)0.2+0.3+0.4+0.50.2×0.3×0.4×0.5(2)2215÷(3512-21116)×258+1823(3)(123-1.6)÷[(3.15+11320)×134]×12.6.

题目详情
化简.
(1)
0.2+0.3+0.4+0.5
0.2×0.3×0.4×0.5

(2)2
2
15
÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6.

0.2+0.3+0.4+0.5
0.2×0.3×0.4×0.5

(2)2
2
15
÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6.
0.2+0.3+0.4+0.5
0.2×0.3×0.4×0.5
0.2+0.3+0.4+0.50.2+0.3+0.4+0.50.2×0.3×0.4×0.50.2×0.3×0.4×0.5
2
15
÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6.
2
15
221515
5
12
-2
11
16
)×2
5
8
+18
2
3

(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6.
5
12
551212
11
16
)×2
5
8
+18
2
3

(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6.
11
16
11111616
5
8
+18
2
3

(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6.
5
8
5588
2
3

(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6.
2
3
2233
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6.
2
3
2233
13
20
)×1
3
4
]×12.6.
13
20
13132020
3
4
]×12.6.
3
4
3344
▼优质解答
答案和解析
(1)
0.2+0.3+0.4+0.5
0.2×0.3×0.4×0.5

=
1.4
0.012

=116
2
3


(2)2
2
15
÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
0.2+0.3+0.4+0.5
0.2×0.3×0.4×0.5
0.2+0.3+0.4+0.50.2+0.3+0.4+0.50.2+0.3+0.4+0.50.2×0.3×0.4×0.50.2×0.3×0.4×0.50.2×0.3×0.4×0.5,
=
1.4
0.012

=116
2
3


(2)2
2
15
÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
1.4
0.012
1.41.41.40.0120.0120.012,
=116
2
3


(2)2
2
15
÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
2
3
222333;

(2)2
2
15
÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
2
15
222151515÷(3
5
12
-2
11
16
)×2
5
8
+18
2
3

=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
5
12
555121212-2
11
16
)×2
5
8
+18
2
3

=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
11
16
111111161616)×2
5
8
+18
2
3

=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
5
8
555888+18
2
3

=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
2
3
222333,
=2
2
15
÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
2
15
222151515÷
35
48
×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
35
48
353535484848×
21
8
+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
21
8
212121888+18
2
3

=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
2
3
222333,
=
32
15
×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
32
15
323232151515×
48
35
×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
48
35
484848353535×
21
8
+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
21
8
212121888+18
2
3

=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
2
3
222333,
=7
17
25
+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
17
25
171717252525+18
2
3

=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
2
3
222333,
=26
26
75


(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
26
75
262626757575;

(3)(1
2
3
-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
2
3
222333-1.6)÷[(3.15+1
13
20
)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
13
20
131313202020)×1
3
4
]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
3
4
333444]×12.6,
=(1
2
3
-1
3
5
)÷[(3
3
20
+1
13
20
)×1
3
4
]×12.6,
=
1
15
÷[
24
5
×
7
4
]×12.6,
=
1
15
÷
42
5
×12.6,
=
1
15
×
5
42
×12.6,
=
1
10
2
3
222333-1
3
5
)÷[(3
3
20
+1
13
20
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