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已知4x-5y+z=7,6x-9y+z=11,则x+y+z的值为?
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已知4x-5y+z=7,6x-9y+z=11,则x+y+z的值为?
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答案和解析
答:
4x-5y+z=7…………(1)
6x-9y+z=11…………(2)
(2)-(1)得:
2x-4y=4
x-2y=2
x=2y+2
代入(1)得:
8y+8-5y+z=7
3y=-z-1
所以:
x+y+z
=2y+2+y+z
=3y+z+2
=-z-1+z+2
=1
4x-5y+z=7…………(1)
6x-9y+z=11…………(2)
(2)-(1)得:
2x-4y=4
x-2y=2
x=2y+2
代入(1)得:
8y+8-5y+z=7
3y=-z-1
所以:
x+y+z
=2y+2+y+z
=3y+z+2
=-z-1+z+2
=1
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