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2次根式计算(√48-3√2)(√18+4√3)-(√3-√2)^21.(√48-3√2)(√18+4√3)-(√3-√2)^22.1/3√2+(√3+√2)/√6-(3√1/2-√3)
题目详情
2次根式计算(√48-3√2)(√18+4√3)-(√3-√2)^2
1.(√48-3√2)(√18+4√3)-(√3-√2)^2
2.1/3√2+(√3+√2)/√6-(3√1/2-√3)
1.(√48-3√2)(√18+4√3)-(√3-√2)^2
2.1/3√2+(√3+√2)/√6-(3√1/2-√3)
▼优质解答
答案和解析
1.(√48-3√2)(√18+4√3)-(√3-√2)^2
=(4√3-3√2)(3√2+4√3)-(√3-√2)^2
=(48-18)-(5-2√6)
=30-5+2√6
=25+2√6
2.1/3√2+(√3+√2)/√6-(3√1/2-√3)
=√2/6+(3√2+2√3)/6-3√2/2+√3
=2√2/3+√3/3--3√2/2+√3
=-5√2/6+4√3/3
=(4√3-3√2)(3√2+4√3)-(√3-√2)^2
=(48-18)-(5-2√6)
=30-5+2√6
=25+2√6
2.1/3√2+(√3+√2)/√6-(3√1/2-√3)
=√2/6+(3√2+2√3)/6-3√2/2+√3
=2√2/3+√3/3--3√2/2+√3
=-5√2/6+4√3/3
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