递等式计算：(13−14)÷12+563.6×98+36×0.235÷[(56−23)×3]9.57-（2.57+3.38）-2.62．

Question

递等式计算：

((1)/(3)−(1)/(4))÷(1)/(2)+(5)/(6)	3.6×98+36×0.2
35÷[((5)/(6)−(2)/(3))×3]	9.57-（2.57+3.38）-2.62．

((1)/(3)−(1)/(4))÷(1)/(2)+(5)/(6)	3.6×98+36×0.2
35÷[((5)/(6)−(2)/(3))×3]	9.57-（2.57+3.38）-2.62．

((1)/(3)−(1)/(4))÷(1)/(2)+(5)/(6) 3.6×98+36×0.2((1)/(3)−(1)/(4))÷(1)/(2)+(5)/(6)((1)/(3)−(1)/(4))÷(1)/(2)+(5)/(6)(1)/(3)1133(1)/(4)1144(1)/(2)1122(5)/(6)55663.6×98+36×0.2 35÷[((5)/(6)−(2)/(3))×3] 9.57-（2.57+3.38）-2.62．35÷[((5)/(6)−(2)/(3))×3]35÷[((5)/(6)−(2)/(3))×3](5)/(6)5566(2)/(3)22339.57-（2.57+3.38）-2.62．

Answer 1

（1）（13−14）÷12+56，=112÷12+56，=16+56，=1；（2）3.6×98+36×0.2，=3.6×（9.8+0.2），=3.6×10，=36；（3）35÷[（56−23）×3]，=35÷[16×3]，=35÷12，=70；（4）9.57-（2.57+3.38）-2.62，=（9.57-2.5...