早教吧作业答案频道 -->数学-->
计算(x-2)/(x^2+3x+2)+6/(2+x-x^2-(x-10)/(x^2-4)
题目详情
计算(x-2)/(x^2+3x+2)+6/(2+x-x^2-(x-10)/(x^2-4)
▼优质解答
答案和解析
(x-2)/(x^2+3x+2)+6/(2+x-x^2)-(x-10)/(x^2-4)=(x-2)/[(x+1)(x+2)]-6/[(x+1)(x-2)]-(x-10)/[(x-2)(x+2)]=[(x-2)^2-6(x+2)-(x-10)(x+1)]/[(x-2)(x+1)(x+2)]=[(x^2-4x+4)-(6x+12)-(x^2-9x-10)]/[(x-2)(x+1)(x+2)]=[-x+...
看了 计算(x-2)/(x^2+3...的网友还看了以下：