早教吧作业答案频道 -->英语-->
英语翻译InconformitywiththeapplicablelawsoftheStateofDelawareandthebylawsofXGroup,Inc.,aDelawarecorporation(the“Corporation”),theundersigned,beingthesoledirectoroftheCorporation,herebyconsentstoandadoptsthefoll
题目详情
英语翻译
In conformity with the applicable laws of the State of Delaware and the bylaws of XGroup,Inc.,a Delaware corporation (the “Corporation”),the undersigned,being the sole director of the Corporation,hereby consents to and adopts the following resolutions and takes the following actions with the same force and effect as if such resolutions had been duly adopted and such actions duly taken at a meeting of the board of directors of the Corporation (the “Board”) duly called and convened for such purpose on the date first set forth above,with a full quorum present and acting throughout.
In conformity with the applicable laws of the State of Delaware and the bylaws of XGroup,Inc.,a Delaware corporation (the “Corporation”),the undersigned,being the sole director of the Corporation,hereby consents to and adopts the following resolutions and takes the following actions with the same force and effect as if such resolutions had been duly adopted and such actions duly taken at a meeting of the board of directors of the Corporation (the “Board”) duly called and convened for such purpose on the date first set forth above,with a full quorum present and acting throughout.
▼优质解答
答案和解析
按照美国特拉华州的适用法律和XGroup公司是一家特拉华公司(以下简称“公司”)的签署,是该公司唯一董事,现同意附例,采用符合下列决议和采用具有相同效力及效果,如果这样的决议已正式通过并适当考虑这种行动在该科技园公司(“董事会”)正式召开董事会会议的日期,并为此目的而召开的下列行动第一上述规定,具有完整的法定人数及署理各地.
看了 英语翻译Inconformi...的网友还看了以下:
A是n阶矩阵,r(A+E)+r(A-E)=n,证明A^2=E稍微具体一点行不。 2020-04-05 …
设n阶实方阵A=A^2,E为n阶单位矩阵,证明:R(A)+R(A-E)=n 2020-04-05 …
一道线性代数的题:设A为n阶方阵,A不等于E,且R(A+3E)+R(A-E)=n,则A的一个特征值 2020-05-14 …
设A是n阶矩阵A^2=E,证明r(A+E)+r(A-E)=n,的一步证明过程不懂由A^2=E,得A 2020-05-14 …
设A为n阶矩阵有A的2次方等于E.求证r(A+E)+r(A-E)=n. 2020-05-14 …
设n方阵A满足A^2=A,E为n阶单位矩阵,证明R(A)+R(A-E)=n 2020-05-15 …
设n阶矩阵A满足A*A=A,E为n阶单位阵,证明:R(A)+R(A-E)=n 2020-05-15 …
设A为n*n矩阵,证明:如果A^2=E,那么R(A+E)+R(A-E)=n 2020-05-15 …
线性代数求解有n阶矩阵A,满足(A+E)(A-E)=0,怎么得出R(A+E)+R(A-E)≤n不懂 2020-06-28 …
1、已知n阶矩阵A满足:R(A+E)+R(A-E)=n,证A(A+2E)(A+4E)-3(A+2E) 2020-11-03 …