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设实数x,y满足X≥0,Y≥0,X+Y≤3,2X+Y≤4,则Z=3X+2Y的最大值
题目详情
设实数x,y满足X≥0,Y≥0,X+Y≤3,2X+Y≤4,则Z=3X+2Y的最大值
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答案和解析
0<=x<=1
0<=y<=2
3X+2Y最大值为7
0<=y<=2
3X+2Y最大值为7
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