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cos215°−cos275°+2tan15°1−tan215°=（）A．−536B．536C．−24D．24
题目详情
cos215°−cos275°+
=（ ）
A．−
B．
C．−
D．
cos215°−cos275°+
=（ ）
A．−
B．
C．−
D．
s215°−cos275°+
=（ ）
A．−
B．
C．−
D．
s215°−cos275°+
=（ ）
A．−
B．
C．−
D．
215°−cos275°+
=（ ）
A．−
B．
C．−
D．
s275°+
=（ ）
A．−
B．
C．−
D．
s275°+
=（ ）
A．−
B．
C．−
D．
275°+
=（ ）
A．−
B．
C．−
D．
2tan15° 2tan15° 1−tan215° 1−tan215° tan215°tan215°215°
−
B．
C．−
D．
5
5
3 3 6 6
C．−
D．
5
5
3 3 6 6
−
D．
2 2 4 4
2 2 4 4
| 2tan15° |
| 1−tan215° |
A．−
5
| ||
| 6 |
B．
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
| 2tan15° |
| 1−tan215° |
A．−
5
| ||
| 6 |
B．
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
| 2tan15° |
| 1−tan215° |
A．−
5
| ||
| 6 |
B．
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
| 2tan15° |
| 1−tan215° |
A．−
5
| ||
| 6 |
B．
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
| 2tan15° |
| 1−tan215° |
A．−
5
| ||
| 6 |
B．
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
| 2tan15° |
| 1−tan215° |
A．−
5
| ||
| 6 |
B．
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
| 2tan15° |
| 1−tan215° |
A．−
5
| ||
| 6 |
B．
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
| 2tan15° |
| 1−tan215° |
A．−
5
| ||
| 6 |
B．
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
| 2tan15° |
| 1−tan215° |
−
5
| ||
| 6 |
B．
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
5
| ||
| 6 |
| 3 |
| 3 |
| 3 |
5
| ||
| 6 |
C．−
| ||
| 4 |
D．
| ||
| 4 |
5
| ||
| 6 |
| 3 |
| 3 |
| 3 |
−
| ||
| 4 |
D．
| ||
| 4 |
| ||
| 4 |
| 2 |
| 2 |
| 2 |
| ||
| 4 |
| ||
| 4 |
| 2 |
| 2 |
| 2 |
▼优质解答
答案和解析
cos215°−cos275°+
=cos215°-cos2（90°-15°）+tan30°
=cos215°-sin215°+tan30°
=cos30°+tan30°
=
+
=
．
故选B cos215°−cos275°+
=cos215°-cos2（90°-15°）+tan30°
=cos215°-sin215°+tan30°
=cos30°+tan30°
=
+
=
．
故选B 215°−cos275°+
=cos215°-cos2（90°-15°）+tan30°
=cos215°-sin215°+tan30°
=cos30°+tan30°
=
+
=
．
故选B 275°+
2tan15° 2tan15° 2tan15°1−tan215° 1−tan215° 1−tan215°215°
=cos2215°-cos22（90°-15°）+tan30°
=cos2215°-sin2215°+tan30°
=cos30°+tan30°
=
+
=
．
故选B
3 3 32 2 2+
=
．
故选B
3 3 33 3 3
=
．
故选B
5
5
5
3 3 36 6 6．
故选B
| 2tan15° |
| 1−tan215° |
=cos215°-cos2（90°-15°）+tan30°
=cos215°-sin215°+tan30°
=cos30°+tan30°
=
| ||
| 2 |
| ||
| 3 |
=
5
| ||
| 6 |
故选B cos215°−cos275°+
| 2tan15° |
| 1−tan215° |
=cos215°-cos2（90°-15°）+tan30°
=cos215°-sin215°+tan30°
=cos30°+tan30°
=
| ||
| 2 |
| ||
| 3 |
=
5
| ||
| 6 |
故选B 215°−cos275°+
| 2tan15° |
| 1−tan215° |
=cos215°-cos2（90°-15°）+tan30°
=cos215°-sin215°+tan30°
=cos30°+tan30°
=
| ||
| 2 |
| ||
| 3 |
=
5
| ||
| 6 |
故选B 275°+
| 2tan15° |
| 1−tan215° |
=cos2215°-cos22（90°-15°）+tan30°
=cos2215°-sin2215°+tan30°
=cos30°+tan30°
=
| ||
| 2 |
| ||
| 3 |
=
5
| ||
| 6 |
故选B
| ||
| 2 |
| 3 |
| 3 |
| 3 |
| ||
| 3 |
=
5
| ||
| 6 |
故选B
| ||
| 3 |
| 3 |
| 3 |
| 3 |
=
5
| ||
| 6 |
故选B
5
| ||
| 6 |
| 3 |
| 3 |
| 3 |
故选B
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