请问裂项公式d/[n(n+d)]=1/n-1/(n+d)的推导过程是怎么样的?

Question

请问裂项公式 d/[n(n+d)]=1/n-1/(n+d)的推导过程是怎么样的?

Answer 1

右推左吧
1/n-1/(n+d) = (n+d-n)/(n(n+d))
=d/[n(n+d)]