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lim(x→0){[sinx-sin(sinx)]sinx}/x^4
题目详情
lim(x→0){[sinx-sin(sinx)]sinx}/x^4
▼优质解答
答案和解析
lim(x→0){[sinx-sin(sinx)]sinx}/x^4
=lim(x→0){[sinx-sin(sinx)]x}/x^4
=lim(x→0)[sinx-sin(sinx)]/x³
=lim(x→0){[cosx-cos(sinx)cosx]/3x²
=lim(x→0){[-sinx+sin(sinx)cos²x+sinxcos(sinx)]/6x
=lim(x→0)[-sinx/6x+sin(sinx)cos²x/6x+sinxcos(sinx)/6x]
=-1/6+lim(x→0)sinx cos²x/6x+1/6
=1/6
=lim(x→0){[sinx-sin(sinx)]x}/x^4
=lim(x→0)[sinx-sin(sinx)]/x³
=lim(x→0){[cosx-cos(sinx)cosx]/3x²
=lim(x→0){[-sinx+sin(sinx)cos²x+sinxcos(sinx)]/6x
=lim(x→0)[-sinx/6x+sin(sinx)cos²x/6x+sinxcos(sinx)/6x]
=-1/6+lim(x→0)sinx cos²x/6x+1/6
=1/6
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