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若|x-1|+(xy-2)的平方=0,求:1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+……+1/(x+2006)(y+2006)的值
题目详情
若|x-1|+(xy-2)的平方=0,求:
1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+……+1/(x+2006)(y+2006)的值
1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+……+1/(x+2006)(y+2006)的值
▼优质解答
答案和解析
由题意可知x=1,y=2,(因为要全都=0) 题目就变成1/(1*2)+1/(2*3).1/(2007*2008) 在拆分 变成1-1/2+1/2-1/3+1/3-1/4..1/2007-1/2008= 1-1/2008= 2007/2008
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