(1+r)的200次方等于2000这个算术式的解答步骤是怎样的?谁还记得,

Question

(1+r)的200次方等于2000 这个算术式的解答步骤是怎样的?谁还记得,

Answer 1

(1 +r)^200 = 2000 ==> lg (1+r)^200 = lg2000 ==> 200 lg (1+r) = 3 + lg2 ==> lg (1+r) = (3 + lg2) / 200 ==> 1 + r = 10^[(3+lg2) / 200] ==> r = 10^[(3+lg2) / 200] - 1