(√3+i)(cosπ/3+isnπ/3)/(cos15+isin15°)的3次方

Answer 1

原式=2(cosπ/6+isinπ/6)(cosπ/3+isnπ/3)/(cosπ/4+isnπ/4)
=2[cos(π/6+π/3-π/4)+isin(π/6+π/3-π/4)]
=2(cosπ/4+isinπ/4)
=√2+i√2