x十y等于123,y十z等于71,z十x等于98,求xyz各多少?

Question

x十y等于123,y十z等于71,z十x等于98,求xyz各多少?

Answer 1

x+y=123
y+z=71
z+x=98
三式相加得2(x+y+z)=292
所以x+y+z=146
所以x=(x+y+z)-(y+z)=146-71=75
y=(x+y+z)-(z+x)=146-98=48
z=(x+y+z)-(x+y)=146-123=23
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