扔硬币十次其中九次是同一面的概率问题正确答案是(10+1)×(1/2)e10=0.0107,还有个抛100次的问题,更加看不懂,Amultiple-comparisonsproblemarisesifonewantedtousethistest(whichisappropriatefortestingthe

Question

扔硬币十次其中九次是同一面的概率问题
正确答案是(10 + 1) × (1/2)e10 = 0.0107,
还有个抛100次的问题,更加看不懂,
A
multiple-comparisons problem arises if one wanted to use this test
(which is appropriate for testing the fairness of a single coin),to
test the fairness of many coins.Imagine if one was to test 100 fair
coins by this method.Given that the probability of a fair coin coming
up 9 or 10 heads in 10 flips is 0.0107,one would expect that in
flipping 100 fair coins ten times each,to see a particular
(i.e.,pre-selected) coin come up heads 9 or 10 times would still be
very unlikely,but seeing any coin behave that way,without concern for
which one,would be more likely than not.Precisely,the likelihood that
all 100 fair coins are identified as fair by this criterion is (1 − 0.0107)100
≈ 0.34.Therefore the application of our single-test coin-fairness
criterion to multiple comparisons would be more likely to falsely
identify at least one fair coin as unfair.

Answer 1

9次同一面,一次不同面.共抛10次.所以是2*(1/2)e10=(1/2)e9（可以正面,也可以反面）
可以第一次不同,其它九次相同,
可以第二次不同,其它九次相同,
共10种
正确答案应该是：10 × (1/2)e9
你的答案里包括10次同一面.