积分号上限(x^2)下限(0)sint/(根号(1+t^2)),y=

Question

积分号上限(x^2)下限(0)sint/(根号(1+ t^2)),y=

Answer 1

G(x) = ∫ sintdt/√(1+t^2)
G'(x) = 2xsin(x^2)/√(1+x^4)