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当m满足什么条件是,关于x的方程m/(x-2)(x+1)=x/x+1-x-1/x-2的解为正数
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答案和解析
m/[(x+1)(x-2)]-x/(x+1)-(x-1)/(x-2)=0
m/(x+1)(x-2)-[x(x-2)-(x+1)(x-1)]/[(x+1)(x-2)]=0
m/(x+1)(x-2)-(1-2x)/[(x+1)(x-2)]=0
(2x-1+m)/[(x+1)(x-2)]=0
2x-1+m=0
x=(1-m)/2>0
m
m/(x+1)(x-2)-[x(x-2)-(x+1)(x-1)]/[(x+1)(x-2)]=0
m/(x+1)(x-2)-(1-2x)/[(x+1)(x-2)]=0
(2x-1+m)/[(x+1)(x-2)]=0
2x-1+m=0
x=(1-m)/2>0
m
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