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已知x比y等于2比3,求(x的平方乖y的平方/xy除以中括号(x+y)乘(x-y/x)的平方中
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已知x比y等于2比3,求(x的平方乖y的平方/xy除以中括号(x+y)乘(x-y/x)的平方中
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答案和解析
已知x比y等于2比3,
设x=2t
则y=3t
(x²y²)/xy÷[(x+y)(x-y)²/x]
=xy÷[(x+y)(x-y)²/x]
=2t*3t÷[(2t+3t)(2t-3t)²/2t]
=6t²÷[5t*t²/2t]
=6t²÷(5t²/2)
=2.4
设x=2t
则y=3t
(x²y²)/xy÷[(x+y)(x-y)²/x]
=xy÷[(x+y)(x-y)²/x]
=2t*3t÷[(2t+3t)(2t-3t)²/2t]
=6t²÷[5t*t²/2t]
=6t²÷(5t²/2)
=2.4
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