在扇形中，已知半径为1，圆心角为120°，则弧长是2π32π3，扇形面积是2π32π3．

Question

在扇形中，已知半径为1，圆心角为120°，则弧长是

(2π)/(3)

(2π)/(3)

，扇形面积是

(2π)/(3)

(2π)/(3)

．

(2π)/(3)

(2π)/(3)(2π)/(3)2π2π33

(2π)/(3)

(2π)/(3)(2π)/(3)2π2π33

(2π)/(3)

(2π)/(3)(2π)/(3)2π2π33

(2π)/(3)

(2π)/(3)(2π)/(3)2π2π33

Answer 1

扇形的弧长是L=(120π•1)/(180)=(2π)/(3)
扇形的面积是 (120)/(360)πr²=(2π)/(3)．
故答案为：(2π)/(3)；(2π)/(3) (120π•1)/(180)120π•1120π•1120π•1180180180=(2π)/(3)
扇形的面积是 (120)/(360)πr²=(2π)/(3)．
故答案为：(2π)/(3)；(2π)/(3) (2π)/(3)2π2π2π333
扇形的面积是 (120)/(360)πr²=(2π)/(3)．
故答案为：(2π)/(3)；(2π)/(3) (120)/(360)120120120360360360πr²2=(2π)/(3)．
故答案为：(2π)/(3)；(2π)/(3) (2π)/(3)2π2π2π333．
故答案为：(2π)/(3)；(2π)/(3) (2π)/(3)2π2π2π333；(2π)/(3) (2π)/(3)2π2π2π333