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1.计算:(1+(2^(-1/8))(二的负八分之一次幂))(1+(2^(-1/4)))(1+(2^(-1/2)))2.已知f(x)=x^a,且f(x)的图像过点(8,1/4),求f(27)的值
题目详情
1.计算:(1+(2^(-1/8))(二的负八分之一次幂))(1+(2^(-1/4)))(1+(2^(-1/2)))
2.已知f(x)=x^a,且f(x)的图像过点(8,1/4),求f(27)的值
2.已知f(x)=x^a,且f(x)的图像过点(8,1/4),求f(27)的值
▼优质解答
答案和解析
1
(1+(2^(-1/8))(二的负八分之一次幂))(1+(2^(-1/4)))(1+(2^(-1/2)))
=(1+(2^(-1/8))(二的负八分之一次幂))(1+(2^(-1/4)))(1+(2^(-1/2))) *(1-(2^(-1/8))/(1-(2^(-1/8))
=[1-2^(-1)]/[1-2^(-1/8)]
=1/[2-2^(7/8)]
2
f(x)=x^a
1/4=8^a
2^(-2)=2^(3a)
3a=-2
a=-2/3
f(x)=x^(-2/3)
f(27)=27^(-2/3)=3^(-3*2/3)=3^(-2)=1/9
(1+(2^(-1/8))(二的负八分之一次幂))(1+(2^(-1/4)))(1+(2^(-1/2)))
=(1+(2^(-1/8))(二的负八分之一次幂))(1+(2^(-1/4)))(1+(2^(-1/2))) *(1-(2^(-1/8))/(1-(2^(-1/8))
=[1-2^(-1)]/[1-2^(-1/8)]
=1/[2-2^(7/8)]
2
f(x)=x^a
1/4=8^a
2^(-2)=2^(3a)
3a=-2
a=-2/3
f(x)=x^(-2/3)
f(27)=27^(-2/3)=3^(-3*2/3)=3^(-2)=1/9
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