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y=cos(x-π/6)[√3sin(x-π/6)+cos(x-π/6)]怎么化简(求最值)化简步骤详细一点,
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y=cos(x-π/6)[√3sin(x-π/6)+cos(x-π/6)]怎么化简(求最值)化简步骤详细一点,
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答案和解析
y=√3sin(x-π/6) cos(x-π/6)+cos(x-π/6)cos(x-π/6)
=√3 /2 sin(2x-π/3)+ 1/2 (cos(2x-π/3)+ 1)
=sin(2x-π/3+π/6)+1/2
=sin (2x-π/6)+1/2
将2x-π/6看成整体,求sin(2x-π/6)的范围,再求y
=√3 /2 sin(2x-π/3)+ 1/2 (cos(2x-π/3)+ 1)
=sin(2x-π/3+π/6)+1/2
=sin (2x-π/6)+1/2
将2x-π/6看成整体,求sin(2x-π/6)的范围,再求y
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