英文版-两道关于污水处理的题目(涉及化学）1.slowsandfiltrationiscommonlyusedfordrinkingwatertreatmentforthesakeoflowcostsandsimpleoperation.Thisprocesscanachievealogremovalof4virusesbutonlyalogremoval

Question

英文版-两道关于污水处理的题目(涉及化学）
1.slow sand filtration is commonly used for drinking water treatment for the sake of low costs and simple operation. This process can achieve a log removal of 4 viruses but only a log removal of 2.3 for bacteria. Explain the difference.
2.A chemically-enhanced primary treatment (CEPT) treatment plant with a flow of 0.045m^3/s is dosing ferric chloride(FeCl3) at 10mg/L. The suspended solid concentrations in the influent and treated wastewater are 47mg/L and 5 mg/L, respectively. Assume that all ferric chloride is settled out as ferric hydroxide(Fe(OH)3)( atomic weights : H=1g/mol; C=12g/mol; O=16g/mol; Cl=35.5g/mol; Fe =56g/mol), the solid content of the sludge is 1.05% by weight, and the bulk density of the sludge is 1060kg/m^3. Estimate the volume of sludge that must be disposed of each day(m^3/d).Given that
Fecl3+3HCO3- →Fe(OH)3(s) +3CO2+3Cl-

Answer 1

0.045米立方公尺/秒的流量经化学强化一级处理（CEPT）处理厂投加10mg/ L三氯化铁（氯化铁）.悬浮固体的进水和处理后的废水浓度分别是47mg/ L和5mg / L.假设所有三氯化铁反应生成氢氧化铁（Fe（OH）3）（原子质量：H =1g/mol C =12克/摩尔,O =16g/摩尔; CL=35.5g/摩尔; Fe =56克/摩尔）,污泥的固体含量为1.05％,堆积淤泥密度的是1060千克/立方公尺.估计污泥必须加以处置的每一天（立方公尺/天）.
氯化铁+3HCO3-→铁（OH）3（S）+3CO2+3Cl-
给你翻译一下,用他给的离子反应式计算就行了
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