将多项式x^2ny^m-3x2n-1y^m+1+4x^2n+1y^m-1-2分之3x^2n+3y^m-2先按x的降幂排列,在按x的升幂排列急急急急急急急急急急急急急啊

Question

将多项式x^2ny^m-3x2n-1y^m+1+4x^2n+1y^m-1-2分之3x^2n+3y^m-2先按x的降幂排列,在按x的升幂排列
急急急急急急急急急急急急急啊

Answer 1

将多项式x^(2n)y^(m)-3x^(2n-1)y^(m+1)+4x^(2n+1)y^(m-1)-2分之3x^(2n+3)y^(m-2)先按x的降幂排列,可表示为：-2分之3x^(2n+3)y^(m)+4x^(2n+1)y^(m-1) +x^(2n)y^(m)-3x^(2n-1)y^(m+1)
再按x的升幂排列为-3x^(2n-1)y^(m+1)+x^(2n)y^(m)+4x^(2n+1)y^(m-1) -2分之3x^(2n+3)y^(m-2)