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诺1/x-1/y=3求2x+3xy-2y/x-2xy-y的值，
题目详情
诺1/x-1/y=3 求2x+3xy-2y/x-2xy-y的值，
▼优质解答
答案和解析
1/x-1/y=3
(y-x)/(xy)=3
y-x=3xy
x-y=-3xy
(2x+3xy-2y)/(x-2xy-y)
=[2(x-y)+3xy]]/[(x-y)-2xy]
=(-6xy+3xy)/(-3xy-2xy)
=(-3)/(-5)
=3/5
(y-x)/(xy)=3
y-x=3xy
x-y=-3xy
(2x+3xy-2y)/(x-2xy-y)
=[2(x-y)+3xy]]/[(x-y)-2xy]
=(-6xy+3xy)/(-3xy-2xy)
=(-3)/(-5)
=3/5
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