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2道gre数学题Ifrandsarepositiveintigers,eachgreaterthan1,andif11(s-1)=13(r-1),whatistheleastpossiblevalueofr+s?A.2B.11C.22D.24E.26Whichofthefollowingisequalto1/4of0.01percent?A.0.000025B.0.00025C.0.0025D.0.025E.

题目详情
2道gre数学题
If r and s are positive intigers,each greater than 1,and if 11(s-1)=13(r-1),what is the least possible value of r+s?
A.2 B.11 C.22 D.24 E.26
Which of the following is equal to 1/4 of 0.01 percent?
A.0.000025 B.0.00025 C.0.0025 D.0.025 E.0.25
▼优质解答
答案和解析
1、r和s是大于1的整数,11(s-1)=13(r-1),那么11s+2=13r
最小的情况s=14,r=12,s+r=26,选E
2、0.01 percent是百分之0.01,也就是0.0001,它的四分之一就是0.000025,选A