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推倒a/sinA=b/sinB=c/sinC=(a+b+c)/(sinA+sinB+sinC)
题目详情
推倒a/sinA=b/sinB=c/sinC=(a+b+c)/(sinA+sinB+sinC)
▼优质解答
答案和解析
根据正弦定理,设a/sinA=b/sinB=c/sinC=ka=ksinA,b=ksinB,c=ksinC(a+b+c)/﹙sinA+sinB+sinC﹚=(ksinA+ksinB+ksinC)/﹙sinA+sinB+sinC﹚=k=a/sinA=b/sinB=c/sinC
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