己知abc≠0,若m=2a/|a|x3b/|b|x4c/|c|,则㎡+2m+1

Question

己知abc≠0,若m=2a/|a|x3b/|b|x4c/|c|,则㎡+2m+1

Answer 1

a/|a|,b/|b|,c/|c|中若3个都为正或1正2负,则m=2x3x4=24；㎡+2m+1=（m+1）^2=25^2=625;若3个都为负或2正1负,则m=-2x3x4=-24；㎡+2m+1=（m+1）^2=23^2=529;