数学calculus题目aparticlemovesalongthexaxissothatatanytimet>0itsaccelerationisgivenbya(t)=ln(1+2^t)ifthevelocityoftheparticleis2attime1thenvelocityoftheparticleattimet=2is

Question

数学calculus题目
a particle moves along the x axis so that at any time t>0 its acceleration is given by a(t)=ln(1+2^t) if the velocity of the particle is 2 at time 1 then velocity of the particle at time t=2 is

Answer 1

先读懂题,不废话了,关键就是告你了加速度时间变化关系：a(t)=ln(1+2^t)
和起始速度是2（这里的起始点是1s）
然后,我们知道,图像上速度就是加速度的面积,所以,求a(t)=ln(1+2^t)在1-2的图像面积,最后加上起始速度2就行了...
结果我是算不了...微积分学的不好...
v=vo+0.5at?...v=v0+at...