早教吧作业答案频道 -->数学-->
已知数列Bn=1/(n^2+2n),其前n项和为Tn,求证Tn
题目详情
已知数列Bn=1/(n^2+2n),其前n项和为Tn,求证Tn
▼优质解答
答案和解析
Bn=1/(n^2+2n)=1/[n(n+2)]=1/2*[1/n-1/(n+2)]
Tn=1/2*(1-1/3)+1/2*(1/2-1/4)+1/2*(1/3-1/5)+1/2*(1/4-1/6)+...+1/2*[1/n-1/(n+2)]
=1/2*[1-1/3+1/2-1/4+1/3-1/5+1/4-1/6+.+1/n-1/(n+2)]
=1/2[1+1/2-1/(n+1)-1/(n+2)]
Tn=1/2*(1-1/3)+1/2*(1/2-1/4)+1/2*(1/3-1/5)+1/2*(1/4-1/6)+...+1/2*[1/n-1/(n+2)]
=1/2*[1-1/3+1/2-1/4+1/3-1/5+1/4-1/6+.+1/n-1/(n+2)]
=1/2[1+1/2-1/(n+1)-1/(n+2)]
看了 已知数列Bn=1/(n^2+...的网友还看了以下：