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设Sn为等差数列的前n项和S3=4a3,S7=-2,则a9=

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设Sn为等差数列的前n项和S3=4a3,S7=-2,则a9=
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答案和解析
a(n) = a + (n-1)d.
s(n) = na + n(n-1)d/2.
s(3) = 3a + 3d = 4a(3) = 4[a+2d] = 4a + 8d, a = -5d.
-2 = s(7) = 7a + 21d = -35d + 21d = -14d. d = 1/7,
a = -5/7.
a(9) = a + 8d = -5/7 + 8/7 = 3/7