1.解分式方程3/x+1/(x-1)+4/(x-2)+4/(x-3)+1/(x-4)+3/(x-5)=02.解方程2x^4+3x^3-16x^2+3x+2=0好的话有追加分哦,..不想浪费分.

Answer 1

【1】
原式＝4*(361*x-445*x^2+226*x^3-50*x^4+4*x^5-90)/x/(x-1)/(x-2)/(x-3)/(x-4)/(x-5)＝0
即：(361*x-445*x^2+226*x^3-50*x^4+4*x^5-90)＝0
(2*x-5)*(2*x^2-10*x+9)*(x^2-5*x+2)＝0
x有五个根,【“x^(1/2)”表示“x的开方”】
x＝
[ 5/2]
[ 5/2+1/2*7^(1/2)]
[ 5/2-1/2*7^(1/2)]
[ 5/2+1/2*17^(1/2)]
[ 5/2-1/2*17^(1/2)]
【2】2*x^4+3*x^3-16*x^2+3*x+2＝0
(x-2)*(2*x-1)*(x^2+4*x+1)＝0
x＝
[ 2]
[ 1/2]
[ -2+3^(1/2)]
[ -2-3^(1/2)]