计算题①-23÷(−2−14)×(−13)2−3281+1②（-38+712）÷（-124）+(−716)÷(−134+[50−(79−1112+16)×(−6)2]÷(−7)2）③[50−(79−1112+16)×(−6)2]÷(−7)2④-12-[2-（1+13×0.5）]÷[32-（-2）2]．

Question

计算题
①-2³÷(−2−(1)/(4))×(−(1)/(3))2−(32)/(81)+1
②（-(3)/(8)+(7)/(12)）÷（-(1)/(24)）+(−(7)/(16))÷(−1(3)/(4)+[50−((7)/(9)−(11)/(12)+(1)/(6))×(−6)2]÷(−7)2）
③[50−((7)/(9)−(11)/(12)+(1)/(6))×(−6)2]÷(−7)2
④-1²-[2-（1+(1)/(3)×0.5）]÷[3²-（-2）²]．

Answer 1

（1）原式=-8÷（-(9)/(4)）×(1)/(9)−(32)/(81)+1=-8×（-(4)/(9)）×(1)/(9)−(32)/(81)+1=(32)/(81)−(32)/(81)+1=1；

（2）原式=（-(3)/(8)+(7)/(12)）×（-24）-(7)/(16)÷{−(7)/(4)+[50-（(7)/(9)−(11)/(12)+(1)/(6)）×36]×(1)/(49)}=-5-(7)/(16)÷{−(7)/(4)+[50-（28-33+6）]×(1)/(49)}=-5-(7)/(16)÷[−(7)/(4)+（49×(1)/(49)）]=-5-(7)/(16)×(−(4)/(3))=-5+(7)/(12)=-(53)/(12)；

（3）原式=[50-（(7)/(9)−(11)/(12)+(1)/(6)）×36]×(1)/(49)=[50-（28-33+6）]×(1)/(49)=49×(1)/(49)=1；

（4）原式=-1²-[2-（