173-X=Y1,X+Z=111,31×2+Z=Y1,Y1+Y2=P,P=Z+X+Y2,求P=18是怎么样算出来的.求教.11131和数(P)结论:173-X=Y,111-X=Z,31×2+Z=Y1,X+Z=111Z=0X=1Y2=23P=Z+X+Y1Y1=1Z=1X=0Y2=34Z=2X=9Y2=415Z=3X=8Y2=516Z=4X=7Y2=617Z=5X=6Y2=718Z=

Question

173-X=Y1,X+Z=111,31×2+Z=Y1,Y1+Y2=P,P=Z+X+Y2,求P=18是怎么样算出来的.求教.
111 31 和数(P) 结论:173-X=Y,111-X=Z,31×2+Z=Y1,X+Z=111
Z=0 X=1 Y2=2 3 P=Z+X+Y1 Y1=1
Z=1 X=0 Y2=3 4
Z=2 X=9 Y2=4 15
Z=3 X=8 Y2=5 16
Z=4 X=7 Y2=6 17
Z=5 X=6 Y2=7 18
Z=6 X=5 Y2=8 19
Z=7 X=4 Y2=9 20
Z=8 X=3 Y2=0 11
Z=9 X=2 Y2=1 12
173-X=Y1,X+Z=111,31×2+Z=Y1,Y1+Y2=P,P=Z+X+Y2,求P=18是怎么样算出来的.求教.
111 31 和数(P) 结论:173-X=Y,111-X=Z,31×2+Z=Y1,X+Z=111
Z=0 X=1 Y2=2 3 P=Z+X+Y2 Y1=1
Z=1 X=0 Y2=3 4 说明：①求p=18,即得出y2=7.我问的是在现有Z=2 X=9 Y2=4 15 的条件下（逻辑关系中）怎能求出p=18
Z=3 X=8 Y2=5 16 或y2=7的唯一答案.
Z=4 X=7 Y2=6 17 ②111是N个数的总和,31是N个数个位数
Z=5 X=6 Y2=7 18 之和
Z=6 X=5 Y2=8 19
Z=7 X=4 Y2=9 20
Z=8 X=3 Y2=0 11
Z=9 X=2 Y2=1 12

Answer 1

Y1+Y2=P=Z+X+Y2
Y1=Z+X=173-X=31×2+Z
则有 X+Z=111
Z+2X=173
∴ X=62 Z=49
则Y1=111 Y2可为任意数
题目有错?