早教吧作业答案频道 -->数学-->
因式分解总共10道16x^-49y^16a^-72a+814+12(x-y)+9(x-y)^x³-9x16x的四次方-16ab^-9a^b-b³16-（2a+3b)^-36x^+12xy-y^4x(a-b)-8y(b-a)(x^-5)^+8(x^-5)+16
题目详情
因式分解 总共10道
16x^-49y^
16a^-72a+81
4+12(x-y)+9(x-y)^
x³-9x
16x的四次方-1
6ab^-9a^b-b³
16-（2a+3b)^
-36x^+12xy-y^
4x(a-b)-8y(b-a)
(x^-5)^+8(x^-5)+16
16x^-49y^
16a^-72a+81
4+12(x-y)+9(x-y)^
x³-9x
16x的四次方-1
6ab^-9a^b-b³
16-（2a+3b)^
-36x^+12xy-y^
4x(a-b)-8y(b-a)
(x^-5)^+8(x^-5)+16
▼优质解答
答案和解析
16x^-49y^
=(4x+7y)(4x-7y)
16a^-72a+81
=(4a-9)^
4+12(x-y)+9(x-y)^
=[2+3(x-y)]^
=(2+3x-3y)^
x³-9x
=x(x^-9）
=x(x+3)(x-3)
16x的四次方-1
=(4x^+1)(4x^-1)
=(4x^+1)(2x+1)(2x-1)
6ab^-9a^b-b³
=b(6ab-9a-b^)
16-（2a+3b)^
=[4+(2a+3b)][4-(2a+3b)]
=(4+2a+3b)(4-2a-3b)
-36x^+12xy-y^
=-(36x^-12xy+y^)
=-(6x-y)^2
4x(a-b)-8y(b-a)
=(a-b)(4x+8y)
=4(a-b)(x+2y)
(x^-5)^+8(x^-5)+16
=(x^-5+4)^2
=(x^-1)^
=(x+1)^(x-1)^
=(4x+7y)(4x-7y)
16a^-72a+81
=(4a-9)^
4+12(x-y)+9(x-y)^
=[2+3(x-y)]^
=(2+3x-3y)^
x³-9x
=x(x^-9）
=x(x+3)(x-3)
16x的四次方-1
=(4x^+1)(4x^-1)
=(4x^+1)(2x+1)(2x-1)
6ab^-9a^b-b³
=b(6ab-9a-b^)
16-（2a+3b)^
=[4+(2a+3b)][4-(2a+3b)]
=(4+2a+3b)(4-2a-3b)
-36x^+12xy-y^
=-(36x^-12xy+y^)
=-(6x-y)^2
4x(a-b)-8y(b-a)
=(a-b)(4x+8y)
=4(a-b)(x+2y)
(x^-5)^+8(x^-5)+16
=(x^-5+4)^2
=(x^-1)^
=(x+1)^(x-1)^
看了 因式分解总共10道16x^-...的网友还看了以下：
1.(x²-x+1)的6立方=a12*12+a11*x11+……+a1*x+a0,则a12+a11 2020-05-16 …
函数y=f(x)(x不等于0)是奇函数,且当x属于(0,正无穷)时,为增函数.若f(1)=0,求不 2020-05-16 …
有关因式定理的推论因式定理有2个推论：其一：若多项式f(x)的系数和为0,则f(x)=(x-1)g 2020-06-10 …
f(x)对任意x∈R,都有f(x+△x)-f(x)/△x>0成立,且f(x)的图像经过A(-1,- 2020-06-11 …
设X≥1,比较因为比较x3与x2-x+1的大小解x-（x-x+1）=x-x+x-1=x（x-1）+ 2020-06-18 …
求函数的驻点f'x(x,y)=2xy(4-x-y)-x^2y=0.(1)其中f'x(x,y)中左边 2020-07-11 …
已知f(x)=x^2+x+1,（1）、求f(f(x))的解析式?（2）、证明对任意x属于R,f(- 2020-07-18 …
观察下列式子的因式分解做法：①x2-1=(x-1)(x+1).②x3-1=x3-x+x-1=x（x 2020-07-29 …
1.已知不等式a+2/2=〉X-1/3的结集为X〈=8,则a=（）2.关于X的不等式1.X-a〉= 2020-08-03 …
二次函数..已知f（x）是二次函数若f（x）=0,且f(x)+x+1=f(x+1),试求f（x）的表 2020-12-08 …