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1[5/[2/3]-2又[1/5]×1又[1/44]]/[1又[8/3]+2又[5/12]-2又[1/6]=2(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)=应该不少了吧...
题目详情
1】[5/[2/3]-2又[1/5]×1又[1/44]]/[1又[8/3]+2又[5/12]-2又[1/6]=
2】(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)=
应该不少了吧...
2】(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)=
应该不少了吧...
▼优质解答
答案和解析
1】[5/[2/3]-2又[1/5]×1又[1/44]]/[1又[8/3]+2又[5/12]-2又[1/6]
=(15/2-11/5*45/44) / (11/3+29/12-13/6)
=(15/2-9/4) / (11/3+1/4)
=(21/4) / (47/12)
=63/47
2)
1+0.12+0.23+0.34=A
(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)
=(A-0.34)(A-1)-A(A-0.34-1)
=A^2-0.34A-A+0.34-A^2+0.34A+A
=0.34
=(15/2-11/5*45/44) / (11/3+29/12-13/6)
=(15/2-9/4) / (11/3+1/4)
=(21/4) / (47/12)
=63/47
2)
1+0.12+0.23+0.34=A
(1+0.12+0.23)×(0.12+0.23+0.34)-(1+0.12+0.23+0.34)×(0.12+0.23)
=(A-0.34)(A-1)-A(A-0.34-1)
=A^2-0.34A-A+0.34-A^2+0.34A+A
=0.34
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