3/1*4+3/4*7+3/7*10+.+3/25*28计算过程谢了!计算2001-1/2-1/3-1/4-......1/2001过程1+1/1+2+1/1+2+3+...+1/1+2+3...1.1=1/3+1/()+1/()+1/()+1/()+1/()+1/242.1=1/3+1/()+1/()+1/()+1/()+1/()+1/()+1/241.2.两题括号里填4到23中不

Question

3/1*4+3/4*7+3/7*10+.+3/25*28计算过程谢了!
计算2001-1/2-1/3-1/4-......1/2001过程
1 + 1/1+2 + 1/1+2+3+ ...+ 1/1+2+3...
1.1=1/3+1/( )+1/( )+1/( )+1/( )+1/( )+1/24
2.1=1/3+1/( )+1/( )+1/( )+1/( )+1/( )+1/( )+1/24
1.2.两题括号里填4到23中不同的整数,是算式成立.会几题答几题,

Answer 1

3/1*4+3/4*7+3/7*10+.+3/25*28
=1-1/4+1/4-1/7+1/7-1/10+.+1/25-1/28
=1-1/28
=27/28
题目太多了,分开来提问吧.