甲乙两人同时从A地出发，骑自行车到B地，已知A、B两地的距离为30km，甲每小时比乙多走3km，并且比乙先到40分钟.设乙每小时走xkm，则可列方程为（）A.30x-30x-3=23B.30x-30x+3=23C.30x+3-30x=23D.

Question

(30)/(x)-(30)/(x-3)=(2)/(3)
B. (30)/(x)-(30)/(x+3)=(2)/(3)
C. (30)/(x+3)-(30)/(x)=(2)/(3)
D. (30)/(x-3)-(30)/(x)=(2)/(3)(30)/(x)3030xx(30)/(x-3)3030x-3x-3(2)/(3)2233
(30)/(x)-(30)/(x+3)=(2)/(3)
C. (30)/(x+3)-(30)/(x)=(2)/(3)
D. (30)/(x-3)-(30)/(x)=(2)/(3)(30)/(x)3030xx(30)/(x+3)3030x+3x+3(2)/(3)2233
(30)/(x+3)-(30)/(x)=(2)/(3)
D. (30)/(x-3)-(30)/(x)=(2)/(3)(30)/(x+3)3030x+3x+3(30)/(x)3030xx(2)/(3)2233
(30)/(x-3)-(30)/(x)=(2)/(3)(30)/(x-3)3030x-3x-3(30)/(x)3030xx(2)/(3)2233

Answer 1

设乙每小时走xkm，则甲每小时走（3+x）km，
则可列方程为：(30)/(x)-(30)/(x+3)=(2)/(3)．
故选：B． (30)/(x)303030xxx-(30)/(x+3)=(2)/(3)．
故选：B． (30)/(x+3)303030x+3x+3x+3=(2)/(3)．
故选：B． (2)/(3)222333．
故选：B．